paul | 718e374 | 2002-12-13 20:15:29 +0000 | [diff] [blame] | 1 | /* |
| 2 | * Checksum routine for Internet Protocol family headers (C Version). |
| 3 | * |
| 4 | * Refer to "Computing the Internet Checksum" by R. Braden, D. Borman and |
| 5 | * C. Partridge, Computer Communication Review, Vol. 19, No. 2, April 1989, |
| 6 | * pp. 86-101, for additional details on computing this checksum. |
| 7 | */ |
| 8 | |
| 9 | #include <zebra.h> |
paul | 34204aa | 2005-11-03 09:00:23 +0000 | [diff] [blame] | 10 | #include "checksum.h" |
paul | 718e374 | 2002-12-13 20:15:29 +0000 | [diff] [blame] | 11 | |
paul | 34204aa | 2005-11-03 09:00:23 +0000 | [diff] [blame] | 12 | int /* return checksum in low-order 16 bits */ |
| 13 | in_cksum(void *parg, int nbytes) |
paul | 718e374 | 2002-12-13 20:15:29 +0000 | [diff] [blame] | 14 | { |
paul | 34204aa | 2005-11-03 09:00:23 +0000 | [diff] [blame] | 15 | u_short *ptr = parg; |
paul | 718e374 | 2002-12-13 20:15:29 +0000 | [diff] [blame] | 16 | register long sum; /* assumes long == 32 bits */ |
| 17 | u_short oddbyte; |
| 18 | register u_short answer; /* assumes u_short == 16 bits */ |
| 19 | |
| 20 | /* |
| 21 | * Our algorithm is simple, using a 32-bit accumulator (sum), |
| 22 | * we add sequential 16-bit words to it, and at the end, fold back |
| 23 | * all the carry bits from the top 16 bits into the lower 16 bits. |
| 24 | */ |
| 25 | |
| 26 | sum = 0; |
| 27 | while (nbytes > 1) { |
| 28 | sum += *ptr++; |
| 29 | nbytes -= 2; |
| 30 | } |
| 31 | |
| 32 | /* mop up an odd byte, if necessary */ |
| 33 | if (nbytes == 1) { |
| 34 | oddbyte = 0; /* make sure top half is zero */ |
| 35 | *((u_char *) &oddbyte) = *(u_char *)ptr; /* one byte only */ |
| 36 | sum += oddbyte; |
| 37 | } |
| 38 | |
| 39 | /* |
| 40 | * Add back carry outs from top 16 bits to low 16 bits. |
| 41 | */ |
| 42 | |
| 43 | sum = (sum >> 16) + (sum & 0xffff); /* add high-16 to low-16 */ |
| 44 | sum += (sum >> 16); /* add carry */ |
| 45 | answer = ~sum; /* ones-complement, then truncate to 16 bits */ |
| 46 | return(answer); |
| 47 | } |
Jingjing Duan | efda3bb | 2008-08-13 19:02:03 +0100 | [diff] [blame] | 48 | |
| 49 | /* Fletcher Checksum -- Refer to RFC1008. */ |
| 50 | #define MODX 4102 /* 5802 should be fine */ |
| 51 | |
| 52 | /* To be consistent, offset is 0-based index, rather than the 1-based |
| 53 | index required in the specification ISO 8473, Annex C.1 */ |
| 54 | u_int16_t |
| 55 | fletcher_checksum(u_char * buffer, int len, u_int16_t offset) |
| 56 | { |
| 57 | u_int8_t *p; |
| 58 | int x; |
| 59 | int y; |
| 60 | u_int32_t mul; |
| 61 | u_int32_t c0; |
| 62 | u_int32_t c1; |
| 63 | u_int16_t checksum; |
| 64 | u_int16_t *csum; |
| 65 | int i, init_len, partial_len; |
| 66 | |
| 67 | checksum = 0; |
| 68 | |
| 69 | /* |
| 70 | * Zero the csum in the packet. |
| 71 | */ |
| 72 | csum = (u_int16_t *) (buffer + offset); |
| 73 | *(csum) = checksum; |
| 74 | |
| 75 | p = buffer; |
| 76 | c0 = 0; |
| 77 | c1 = 0; |
| 78 | init_len = len; |
| 79 | |
| 80 | while (len != 0) |
| 81 | { |
| 82 | partial_len = MIN(len, MODX); |
| 83 | |
| 84 | for (i = 0; i < partial_len; i++) |
| 85 | { |
| 86 | c0 = c0 + *(p++); |
| 87 | c1 += c0; |
| 88 | } |
| 89 | |
| 90 | c0 = c0 % 255; |
| 91 | c1 = c1 % 255; |
| 92 | |
| 93 | len -= partial_len; |
| 94 | } |
| 95 | |
| 96 | mul = (init_len - offset)*(c0); |
| 97 | |
| 98 | x = mul - c0 - c1; |
| 99 | y = c1 - mul - 1; |
| 100 | |
| 101 | if (y > 0) |
| 102 | y++; |
| 103 | if (x < 0) |
| 104 | x--; |
| 105 | |
| 106 | x %= 255; |
| 107 | y %= 255; |
| 108 | |
| 109 | if (x == 0) |
| 110 | x = 255; |
| 111 | if (y == 0) |
| 112 | y = 1; |
| 113 | |
| 114 | /* |
| 115 | * Now we write this to the packet. |
| 116 | * We could skip this step too, since the checksum returned would |
| 117 | * be stored into the checksum field by the caller. |
| 118 | */ |
| 119 | buffer[offset] = x; |
| 120 | buffer[offset + 1] = y; |
| 121 | |
| 122 | /* Take care of the endian issue */ |
| 123 | checksum = htons((x << 8) | (y & 0xFF)); |
| 124 | |
| 125 | return checksum; |
| 126 | } |